constexpr std::chrono::year& operator++() noexcept; | (1) | (since C++20) |
constexpr std::chrono::year operator++(int) noexcept; | (2) | (since C++20) |
constexpr std::chrono::year& operator--() noexcept; | (3) | (since C++20) |
constexpr std::chrono::year operator--(int) noexcept; | (4) | (since C++20) |
Adds or subtracts 1 from the year value.
*this += std::chrono::years{1};
*this -= std::chrono::years{1};
(none).
year
after modificationyear
made before modificationIf the result would be outside the range [-32767, 32767], the actual stored value is unspecified.
#include <iostream> #include <chrono> int main() { std::cout << std::boolalpha; std::chrono::year y {2020}; std::cout << (++y == std::chrono::year(2021)) << ' '; std::cout << (--y == std::chrono::year(2020)) << '\n'; using namespace std::literals::chrono_literals; y = 32767y; y++; //< unspecified, see Notes std::cout << static_cast<int>(y) << '\n'; }
Possible output:
true true -32768
adds or subtracts a number of years from a year (public member function) |
|
(C++20) | performs arithmetic on year s (function) |
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