std::chrono::year::operator++, std::chrono::year::operator--

constexpr std::chrono::year& operator++() noexcept;
(1) (since C++20)
constexpr std::chrono::year operator++(int) noexcept;
(2) (since C++20)
constexpr std::chrono::year& operator--() noexcept;
(3) (since C++20)
constexpr std::chrono::year operator--(int) noexcept;
(4) (since C++20)

Adds or subtracts 1 from the year value.

1-2) Performs *this += std::chrono::years{1};
3-4) Performs *this -= std::chrono::years{1};



Return value

1,3) a reference to this year after modification
2,4) a copy of the year made before modification


If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.


#include <iostream>
#include <chrono>
int main()
    std::cout << std::boolalpha;
    std::chrono::year y {2020};
    std::cout << (++y == std::chrono::year(2021)) << ' ';
    std::cout << (--y == std::chrono::year(2020)) << '\n';
    using namespace std::literals::chrono_literals;
    y = 32767y;
    y++; //< unspecified, see Notes
    std::cout << static_cast<int>(y) << '\n';

Possible output:

true true

See also

adds or subtracts a number of years from a year
(public member function)
performs arithmetic on years

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