/TensorFlow 2.4


Shuffle dimensions of x according to a permutation and conjugate the result.

The output y has the same rank as x. The shapes of x and y satisfy: y.shape[i] == x.shape[perm[i]] for i in [0, 1, ..., rank(x) - 1] y[i,j,k,...,s,t,u] == conj(x[perm[i], perm[j], perm[k],...,perm[s], perm[t], perm[u]])

x A Tensor.
perm A Tensor. Must be one of the following types: int32, int64.
name A name for the operation (optional).
A Tensor. Has the same type as x.

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