Finds unique elements in a 1-D tensor.
tf.raw_ops.UniqueWithCounts( x, out_idx=tf.dtypes.int32, name=None )
This operation returns a tensor y
containing all of the unique elements of x
sorted in the same order that they occur in x
. This operation also returns a tensor idx
the same size as x
that contains the index of each value of x
in the unique output y
. Finally, it returns a third tensor count
that contains the count of each element of y
in x
. In other words:
y[idx[i]] = x[i] for i in [0, 1,...,rank(x) - 1]
# tensor 'x' is [1, 1, 2, 4, 4, 4, 7, 8, 8] y, idx, count = unique_with_counts(x) y ==> [1, 2, 4, 7, 8] idx ==> [0, 0, 1, 2, 2, 2, 3, 4, 4] count ==> [2, 1, 3, 1, 2]
Args | |
---|---|
x | A Tensor . 1-D. |
out_idx | An optional tf.DType from: tf.int32, tf.int64 . Defaults to tf.int32 . |
name | A name for the operation (optional). |
Returns | |
---|---|
A tuple of Tensor objects (y, idx, count). | |
y | A Tensor . Has the same type as x . |
idx | A Tensor of type out_idx . |
count | A Tensor of type out_idx . |
© 2020 The TensorFlow Authors. All rights reserved.
Licensed under the Creative Commons Attribution License 3.0.
Code samples licensed under the Apache 2.0 License.
https://www.tensorflow.org/versions/r2.4/api_docs/python/tf/raw_ops/UniqueWithCounts