| Defined in header <type_traits> | ||
|---|---|---|
| template< class Base, class Derived > struct is_pointer_interconvertible_base_of; | (since C++20) | 
If Derived is unambiguously derived from Base and every Derived object is pointer-interconvertible with its Base subobject, or if both are the same non-union class (in both cases ignoring cv-qualification), provides the member constant value equal to true. Otherwise value is false.
If both Base and Derived are non-union class types, and they are not the same type (ignoring cv-qualification), Derived shall be a complete type; otherwise the behavior is undefined.
The behavior of a program that adds specializations for is_pointer_interconvertible_base_of or is_pointer_interconvertible_base_of_v is undefined.
| template< class Base, class Derived >
inline constexpr bool is_pointer_interconvertible_base_of_v =
    is_pointer_interconvertible_base_of<Base, Derived>::value; | (since C++20) | 
| value [static] | trueifDerivedis unambiguously derived fromBaseand everyDerivedobject is pointer-interconvertible with itsBasesubobject, or if both are the same non-union class (in both cases ignoring cv-qualification),falseotherwise(public static member constant) | 
| operator bool | converts the object to bool, returns value(public member function) | 
| operator() (C++14) | returns value(public member function) | 
| Type | Definition | 
|---|---|
| value_type | bool | 
| type | std::integral_constant<bool, value> | 
std::is_pointer_interconvertible_base_of_v<T, U> may be true even if T is a private or protected base class of U.
Let.
U be a complete object type, T be a complete object type with cv-qualification not less than U, u be any valid lvalue of U, reinterpret_cast<T&>(u) always has well-defined result if std::is_pointer_interconvertible_base_of_v<T, U> is true.
If T and U are not the same type (ignoring cv-qualification) and T is a pointer-interconvertible base class of U, then both std::is_standard_layout_v<T> and std::is_standard_layout_v<U> are true.
If T is standard layout class type, then all base classes of T (if any) are pointer-interconvertible base class of T.
| Feature-test macro | Value | Std | Comment | 
|---|---|---|---|
| __cpp_lib_is_pointer_interconvertible | 201907L | (C++20) | Pointer-interconvertibility traits: 
 | 
#include <type_traits>
 
struct Foo {};
 
struct Bar {};
 
class Baz : Foo, public Bar { int x; };
 
class NonStdLayout : public Baz { int y; };
 
static_assert(std::is_pointer_interconvertible_base_of_v<Bar, Baz>);
static_assert(std::is_pointer_interconvertible_base_of_v<Foo, Baz>);
static_assert(not std::is_pointer_interconvertible_base_of_v<Baz, NonStdLayout>);
static_assert(std::is_pointer_interconvertible_base_of_v<NonStdLayout, NonStdLayout>);
 
int main() {}| (C++11) | checks if a type is derived from the other type (class template) | 
| (C++11) | checks if a type is a class (but not union) type and has no non-static data members (class template) | 
| (C++11) | checks if a type is a standard-layout type (class template) | 
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